1
GATE ECE 2012
MCQ (Single Correct Answer)
+2
-0.6
The voltage gain Av of the circuit shown below is GATE ECE 2012 Analog Circuits - Bipolar Junction Transistor Question 32 English
A
$$\left| {{{\rm A}_v}} \right|\, \approx \,200$$
B
$$\left| {{{\rm A}_v}} \right|\, \approx \,100$$
C
$$\left| {{{\rm A}_v}} \right|\, \approx \,20$$
D
$$\left| {{{\rm A}_v}} \right|\, \approx \,10$$
2
GATE ECE 2012
MCQ (Single Correct Answer)
+2
-0.6
The circuit shown is a GATE ECE 2012 Analog Circuits - Operational Amplifier Question 43 English
A
low pass filter with
$${f_3}dB = \,{1 \over {\left( {{R_1} + {R_2}} \right)C}}rad/s$$
B
high pass filter with
$${f_3}dB = \,{1 \over {{R_1}C}}rad/s$$
C
low pass filter with
$${f_3}dB = {1 \over {{R_1}C}}rad/s$$
D
high pass filter with
$${f_3}dB = {1 \over {\left( {{R_1} + {R_2}} \right)C}}rad/s$$
3
GATE ECE 2012
MCQ (Single Correct Answer)
+1
-0.3
Two independent random variable X and Y are uniformly distributed in the interval [ - 1, 1]. The probability that max [X, Y] is less than 1/2 is
A
3/4
B
9/16
C
1/4
D
2/3
4
GATE ECE 2012
MCQ (Single Correct Answer)
+2
-0.6
A BPSK scheme operating over an AWGN channel with noise power spectral density of N02, uses equi-probable signals $$${s_1}\left( t \right) = \sqrt {{{2E} \over T}\,\sin \left( {{\omega _c}t} \right)} $$$
and $$${s_2}\left( t \right) = - \sqrt {{{2E} \over T}\,\sin \left( {{\omega _c}t} \right)} $$$

over the symbol interval, $$(0, T)$$. If the local oscillator in a coherent receiver is ahead in phase by 450 with respect to the received signal, the probability of error in the resulting system is

A
$$Q\left( {\sqrt {{{2E} \over {{N_0}}}} } \right)$$
B
$$Q\left( {\sqrt {{{E} \over {{N_0}}}} } \right)$$
C
$$Q\left( {\sqrt {{{E} \over {{2N_0}}}} } \right)$$
D
$$Q\left( {\sqrt {{{E} \over {{4N_0}}}} } \right)$$