GATE ECE 2012 | GATE ECE Year Wise Previous Years Questions

GATE ECE 2012

MCQ (Single Correct Answer)

-0.3

The diodes and capacitors in the circuit shown are ideal. The voltage v(t) across the diode D1 is GATE ECE 2012 Analog Circuits - Diodes Question 17 English

GATE ECE 2012 Analog Circuits - Diodes Question 17 English

cos (ωt) − 1

sin (ωt)

1 - cos (ωt)

1 - sin (ωt)

GATE ECE 2012

MCQ (Single Correct Answer)

-0.3

The current i_b through the base of a silicon npn transistor is $$1\;+\;0.1\;\cos\left(10000\;\mathrm\pi\;\mathrm t\right)$$ mA . At 300 K, the $$r_\mathrm\pi$$ in the small signal model of the transistor is GATE ECE 2012 Analog Circuits - Bipolar Junction Transistor Question 53 English

GATE ECE 2012 Analog Circuits - Bipolar Junction Transistor Question 53 English

$$250\;\Omega$$

$$27.5\;\Omega$$

$$25\;\Omega$$

$$22.5\;\Omega$$

GATE ECE 2012

MCQ (Single Correct Answer)

-0.6

The voltage gain A_v of the circuit shown below is GATE ECE 2012 Analog Circuits - Bipolar Junction Transistor Question 25 English

$$\left| {{{\rm A}_v}} \right|\, \approx \,200$$

$$\left| {{{\rm A}_v}} \right|\, \approx \,100$$

$$\left| {{{\rm A}_v}} \right|\, \approx \,20$$

$$\left| {{{\rm A}_v}} \right|\, \approx \,10$$

GATE ECE 2012

MCQ (Single Correct Answer)

-0.6

The circuit shown is a GATE ECE 2012 Analog Circuits - Operational Amplifier Question 33 English

low pass filter with
$${f_3}dB = \,{1 \over {\left( {{R_1} + {R_2}} \right)C}}rad/s$$

high pass filter with
$${f_3}dB = \,{1 \over {{R_1}C}}rad/s$$

low pass filter with
$${f_3}dB = {1 \over {{R_1}C}}rad/s$$

high pass filter with
$${f_3}dB = {1 \over {\left( {{R_1} + {R_2}} \right)C}}rad/s$$

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