1
GATE ECE 2011
MCQ (Single Correct Answer)
+2
-0.67
In the circuit shown below, the current I is equal to

GATE ECE 2011 Network Theory - Network Elements Question 2 English
A
$1.4 \angle 0^{\circ} \mathrm{A}$
B
$2.0 \angle 0^{\circ} \mathrm{A}$
C
$2.8 \angle 0^{\circ} \mathrm{A}$
D
$3.2 \angle 0^{\circ} \mathrm{A}$
2
GATE ECE 2011
MCQ (Single Correct Answer)
+2
-0.6
If $$F\left( s \right) = L\left[ {f\left( t \right)} \right] = {{2\left( {s + 1} \right)} \over {{s^2} + 4s + 7}}$$ then the initial and final values of f(t) are respectively
A
0, 2
B
2, 0
C
0, 2/7
D
2/7, 0
3
GATE ECE 2011
MCQ (Single Correct Answer)
+2
-0.6
The first six points of the 8-point DFT of a real valued sequence are 5, 1 - j3, 0, 3- j4, 0 and 3+ j4. The last two points of the DFT are respectively
A
0, 1- j3
B
0, 1+ j3
C
1+j3, 5
D
1 – j3, 5
4
GATE ECE 2011
MCQ (Single Correct Answer)
+1
-0.3
The differential equation $$100{{{d^2}y} \over {dt}} - 20{{dy} \over {dt}} + y = x\left( t \right)$$ describes a system with an input x(t) and output y(t). The system, which is initially relaxed, is excited by a unit step input. The output y(t) can be represented by the waveform
A
GATE ECE 2011 Signals and Systems - Continuous Time Linear Invariant System Question 40 English Option 1
B
GATE ECE 2011 Signals and Systems - Continuous Time Linear Invariant System Question 40 English Option 2
C
GATE ECE 2011 Signals and Systems - Continuous Time Linear Invariant System Question 40 English Option 3
D
GATE ECE 2011 Signals and Systems - Continuous Time Linear Invariant System Question 40 English Option 4
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