1
GATE ECE 2011
MCQ (Single Correct Answer)
+1
-0.3
In the circuit shown below, capacitors C1 and C2 are very large and are shorts at the input frequency. Vi is a small signal input. The gain magnitude $$\left|\frac{{\mathrm V}_0}{{\mathrm V}_\mathrm i}\right|$$ at 10 Mrad/s is GATE ECE 2011 Analog Circuits - Bipolar Junction Transistor Question 54 English
A
maximum
B
minimum
C
unity
D
zero
2
GATE ECE 2011
MCQ (Single Correct Answer)
+2
-0.6
For a BJT, the common-base current gain $$\alpha = \,\,0.98$$ and the colector base junction reverse bias saturation current Ico = 0.6 $$\mu {\rm A}$$. This BJT is connected in the common emitter mode and operated in the active region with a base drive current IB = 20$$\mu {\rm A}$$. The collector current Ic for this mode of operation is
A
0.98 mA
B
0.99 mA
C
1.0 mA
D
1.01 mA
3
GATE ECE 2011
MCQ (Single Correct Answer)
+2
-0.6
For the BJT Q1 in the circuit shown below, $$\beta = \infty ,\,\,\,\,{V_{BEon\,}}\, = \,0.7V,\,\,\,{V_{CEsat}}\, = \,0.7V.$$. The switch is initially closed. at time t = 0, the switch is opened. The time t at which q1 leaves the active region is GATE ECE 2011 Analog Circuits - Bipolar Junction Transistor Question 26 English
A
10 ms
B
25 ms
C
50 ms
D
100 ms
4
GATE ECE 2011
MCQ (Single Correct Answer)
+2
-0.6
A four phase and an eight-phase signal constellation are shown in the figure below. GATE ECE 2011 Communications - Noise In Digital Communication Question 9 English

Assuming high SNR and that all signals are equally probable, the additional average transmitted signal energy required by the 8-PSK signal to achieve the same error probability as the 4-PSK signal is

A
11.90 dB
B
8.73 dB
C
6.79 dB
D
5.33 dB
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