1
MHT CET 2026 17th April Morning Shift
MCQ (Single Correct Answer)
+2
-0
The equations of the tangents to the ellipse $\dfrac{x^2}{16} + \dfrac{y^2}{9} = 1$ making an inclination of $30^\circ$ with the major axis are
A
$x + \sqrt{3}\,y \pm \sqrt{43} = 0$
B
$x - \sqrt{3}\,y \pm \sqrt{43} = 0$
C
$\sqrt{3}\,x - y \pm \sqrt{43} = 0$
D
$x - \sqrt{3}\,y \pm \sqrt{3} = 0$
2
MHT CET 2025 5th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

The eccentric angle of the point $\mathrm{P}(-6,2)$ of the ellipse $\frac{x^2}{48}+\frac{y^2}{16}=1$ is

A

$30^{\circ}$

B

$135^{\circ}$

C

$150^{\circ}$

D

$120^{\circ}$

3
MHT CET 2025 26th April Evening Shift
MCQ (Single Correct Answer)
+2
-0

The tangent to the ellipse $9 x^2+16 y^2=288$ making equal intercepts on the co-ordinate axes intersects the X -axis and the Y -axis in the points $A$ and $B$ respectively. Then $A(\triangle O A B)=$ (where O is origin)

A

$\frac{25}{2}$ sq. units

B

25 sq. units

C

$\frac{25 \sqrt{5}}{2}$ sq. units

D

$25 \sqrt{5}$ sq. units

4
MHT CET 2025 25th April Morning Shift
MCQ (Single Correct Answer)
+2
-0

The eccentricity of the curve represented by $x=3(\cos t+\sin t), y=4(\cos t-\sin t)$ is

A
$\frac{\sqrt{7}}{4}$
B
$\frac{7}{16}$
C
$\frac{\sqrt{7}}{3}$
D
$\frac{\sqrt{8}}{4}$

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