A ray of light travelling through glass of refractive index $$\sqrt{2}$$ is incident on glass-air boundary at an angle of incidence $$45^{\circ}$$. If refractive index of air is 1 , then the angle of refraction will be $$\left[\sin 45^{\circ}=\frac{1}{\sqrt{2}}, \sin 90^{\circ}=1\right]$$

A ray of light is incident at an angle $$i$$ on one face of prism of small angle $$A$$ and emerges normally from the other surface. $$\mu$$ is the refractive index of the material of the prism. The angle of incidence is

The magnifying power of a telescope is high, if its objective and eyepiece have respectively

Glass has refractive index $\mu$ with respect to air and the critical angle for a ray of light going from glass to air is $\theta$. If a ray of light is incident from air on the glass with angle of incidence $\theta$, corresponding angle of refraction is