The approximate value of $3^{2.001}$, if $\log 3=1.0986$ is

The approximate value of $\log _{10} 1002$ is (Given $\log _{10} \mathrm{e}=0.4343$)

If $f(x)=\log _e\left(\frac{1-x}{1+x}\right),|x|<1$, then $f\left(\frac{2 x}{1+x^2}\right)$ is equal to