1
GATE CSE 2018
MCQ (Single Correct Answer)
+2
-0.6
Consider the following statements regarding the slow start phase of the $$TCP$$ congestion control algorithm. Note that $$cwnd$$ stands for the $$TCP$$ congestion window and $$MSS$$ denotes the Maximum Segment Size.

$$(i)$$ $$\,\,\,\,\,\,\,\,\,\,\,$$ The $$cwnd$$ increases by $$2$$ $$MSS$$ on every successful acknowledgment.
$$(ii)$$ $$\,\,\,\,\,\,\,\,\,$$ The $$cwnd$$ approximately doubles on every successful acknowledgement.
$$(iii)$$ $$\,\,\,\,\,\,\,$$ The $$cwnd$$ increases by $$1$$ $$MSS$$ every round trip time.
$$(iv)$$ $$\,\,\,\,\,\,\,\,\,$$ The $$cwnd$$ approximately doubles every round trip time.

Which one of the following is correct?

A
Only $$(ii)$$ and $$(iii)$$ are true
B
Only $$(i)$$ and $$(iii)$$ are true
C
Only $$(iv)$$ is true
D
Only $$(i)$$ and $$(iv)$$ are true
2
GATE CSE 2018
Numerical
+2
-0
Consider an $$IP$$ packet with a length of $$4,500$$ bytes that includes a $$20$$-byte $$IPv$$$$4$$ header and a $$40$$-byte $$TCP$$ header. The packet is forwarded to an $$IPv4$$ router that supports a Maximum Transmission Unit $$(MTU)$$ of $$600$$ bytes. Assume that the length of the $$IP$$ header in all the outgoing fragments of this packet is $$20$$ bytes. Assume that the fragmentation offset value stored in the first fragment is $$0.$$

The fragmentation offset value stored in the third fragment is _______.

Your input ____
3
GATE CSE 2016 Set 1
Numerical
+2
-0
For a host machine that uses the token bucket algorithm for congestion control, the token bucket has a capacity of 1 megabyte and the maximum output rate is 20 megabytes per second. Tokens arrive at a rate to sustain output at a rate of 10 megabytes per second. The token bucket is currently full and the machine needs to send 12 megabytes of data. The minimum time required to transmit the data is __________ seconds.
Your input ____
4
GATE CSE 2015 Set 2
MCQ (Single Correct Answer)
+2
-0.6
Assume that the bandwidth for a TCP connection is 1048560 bits/sec. Let $$\alpha $$ be the value of RTT in milliseconds(rounded off to the nearest integer) after which the TCP window scale option is needed. Let $$\beta $$ be the maximum possible window size the window scale option. Then the values of $$\alpha $$ and $$\beta $$ are
A
63 milliseconds, $$65535 \times {2^{14}}$$
B
63 milliseconds, $$65535 \times {2^{16}}$$
C
500 milliseconds, $$65535 \times {2^{14}}$$
D
63 milliseconds, $$65535 \times {2^{16}}$$
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