1
GATE CSE 2016 Set 1
Numerical
+2
-0
An IP datagram of size 1000 bytes arrives at a router. The router has to forward this packet on a link whose MTU (maximum transmission unit) is 100 bytes. Assume that the size of the IP header is 20 bytes.

The number of fragments that the IP datagram will be divided into for transmission is ________.

Your input ____
2
GATE CSE 2015 Set 3
Numerical
+2
-0
In the network 200.20.11.144/27, the fourth octet (in decimal) of the last IP address of the network which can be assigned to a host is ________.
Your input ____
3
GATE CSE 2015 Set 2
MCQ (Single Correct Answer)
+2
-0.6
Consider the following routing table at an IP router: GATE CSE 2015 Set 2 Computer Networks - Network Layer Question 15 English 1

For each IP address in Group I identify the correct choice of the next hop from Group II using the entries from the routing table above.

GATE CSE 2015 Set 2 Computer Networks - Network Layer Question 15 English 2
A
i - a, ii - c, iii - e, iv - d
B
i - a, ii - d, iii - b, iv - e
C
i - b, ii - c, iii - d, iv - e
D
i - b, ii - c, iii - e, iv - d
4
GATE CSE 2015 Set 2
MCQ (Single Correct Answer)
+2
-0.6
Host A sends a UDP datagram containing 8880 bytes of user data to host B over an Ethernet LAN. Ethernet frames may carry data up to 1500 bytes (i.e. MTU = 1500 bytes). Size of UDP header is 8 bytes and size of IP heard is 20 bytes.There is no option field in IP header How many total number of IP fragments will be transmitted and what will be the contents of offset field in the last fragment?
A
6 and 925
B
6 and 7400
C
7 and 1110
D
7 and 8880
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