1
GATE CSE 1996
MCQ (Single Correct Answer)
+2
-0.6
A solution to the Dining Philosophers Problem which avoids deadlock is
A
ensure that all philosophers pick up the left fork before the right fork.
B
ensure that all philosophers pick up the right fork before the left fork
C
ensure that one particular philosopher picks up the left fork before the right fork, and that all other philosophers pick up the right fork before the left fork
D
None of the above.
2
GATE CSE 1996
Subjective
+2
-0
The concurrent programming constructs fork and join are as below: Fork (label) which creates a new process executing from the specified label join (variable) which decrements the specified synchronization variable (by 1) and terminates the process if the new value is not 0. Show the precedence graph for S1, S2, S3, S4 and S5 of the concurrent program below.
N = 2
M = 2
fork L3
fork L4
S1
L1 : join N
S3
L2: join M
S5
L3:S2
goto L1
L4:S4
goto L2
next:
3
GATE CSE 1992
MCQ (Single Correct Answer)
+2
-0.6
At a particular time of computation the value of a counting semaphore is 7. Then 20 P operations and 15 V operations were completed on this semaphore. The resulting value of the semaphore is:
A
42
B
2
C
7
D
12
4
GATE CSE 1990
Fill in the Blanks
+2
-0
Semaphore operations are atomic because they are implemented within the OS
GATE CSE Subjects
Software Engineering
Web Technologies
EXAM MAP
Medical
NEET
Graduate Aptitude Test in Engineering
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CBSE
Class 12