GATE ECE 1996 | GATE ECE Year Wise Previous Years Questions

GATE ECE 1996

MCQ (Single Correct Answer)

-0.6

In the circuit shown in Fig. is a finite gain amplifier with a gain of K, a very large input impedance, and a very low output impedance. The input impedance of the feedback amplifier with the feedback impedance Z conducted as shown will be GATE ECE 1996 Analog Circuits - Frequency Response Question 7 English

GATE ECE 1996 Analog Circuits - Frequency Response Question 7 English

$$Z\left[ {1 - {1 \over K}} \right]$$

$$Z\left( {1 - K} \right)$$

$$\left[ {{Z \over {K - 1}}} \right]$$

$$\left[ {{Z \over {1 - K}}} \right]$$

GATE ECE 1996

Subjective

-0

A JEFT with V_P = -4V and I_Dss = 12mA is used in the circuit shown in Fig. Assuming the device to be operating in saturation, determine I_D, V_DS and V_GS GATE ECE 1996 Analog Circuits - FET and MOSFET Question 10 English

GATE ECE 1996

MCQ (Single Correct Answer)

-0.6

Value of R in the oscillator shown in the given figure. So chosen that it just oscillates at an angular frequencies of' "$$\omega $$". The value of "$$\omega $$" and the required value of R will respectively be GATE ECE 1996 Analog Circuits - Oscillators Question 6 English

GATE ECE 1996 Analog Circuits - Oscillators Question 6 English

$${10^5}$$ rad/ sec, 2 $$ \times $$$${10^4}$$ $$\Omega $$

$$2 \times {10^4}$$ rad/ sec, $$2 \times {10^4}$$ $$\Omega $$

$$2 \times {10^4}$$ rad/ sec , $${10^5}\,\Omega $$

$${10^{5\,\,}}rad/\sec ,{10^5}\,\Omega $$

GATE ECE 1996

MCQ (Single Correct Answer)

-0.3

The circuit shown in the figure is that of GATE ECE 1996 Analog Circuits - Operational Amplifier Question 86 English

a non-inverting Amplifiers

an inverting Amplifier

an oscillator

a Schmitt trigger

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