RE-NEET 2026 | Electromagnetic Waves Question 1 | Physics

RE-NEET 2026

MCQ (Single Correct Answer)

-1

The following table presents the part of the electromagnetic spectrum and their corresponding major applications.

	Part of the electromagnetic spectrum		Applications
P.	Microwave	I.	For purifying the water
Q.	UV rays	II.	For warming the food
R.	Gamma rays	III.	For AM and FM communication systems
S.	Radio wave	IV.	For treating the Cancer cells

The correct option is:

P-II, Q-IV, R-III, S-I

P-I, Q-II, R-III, S-IV

P-I, Q-IV, R-II, S-III

P-II, Q-I, R-IV, S-III

RE-NEET 2026

MCQ (Single Correct Answer)

-1

An electromagnetic wave travelling in a lossless dielectric medium having a dielectric constant, $\varepsilon_r=9$, has the electric field, $E_x=E_0 \sin \left(k z-2 \pi \times 10^6 t\right) \vee m^{-1}$ where $E_0$ is the amplitude and $k$ is the wave vector. Among the following options, the incorrect choice is

The direction of propagation of the electromagnetic wave is along $+z$

The speed of the electromagnetic wave inside the medium is $10^8 \mathrm{~ms}^{-1}$

The wavelength of the electromagnetic wave inside the medium is 300 m

The magnetic field is given by the relation $B_y=\frac{B_0}{v} \sin \left(k z-2 \pi \times 10^6 t\right)$ where $v$ is the speed of the electromagnetic wave inside the medium

NEET 2026

MCQ (Single Correct Answer)

-1

$$ \text { Match List I with List II: } $$

List-I (Electromagnetic wave)		List-II (Production)
A.	Microwave	I.	Electrons in atoms emit light when they move from a higher energy level to a lower energy level
B.	Visible light	II.	Radioactive decay of nucleus
C.	Gamma rays	III.	Vibration of atoms and molecules
D.	Infra-red rays	IV.	Klystron valve or magnetron valve

Choose the correct answer from the options given below:

A-III, B-I, C-II, D-IV

A-III, B-IV, C-I, D-II

A-IV, B-I, C-II, D-III

A-IV, B-III, C-II, D-I

NEET 2025

MCQ (Single Correct Answer)

-1

The electric field in a plane electromagnetic wave is given by $$ E_z=60 \cos \left(5 x+1.5 \times 10^9 t\right) \mathrm{V} / \mathrm{m}$$ Then expression for the corresponding magnetic field is (here subscripts denote the direction of the field) :

$B z=60 \cos \left(5 x+1.5 \times 10^9 t\right) T$

$B_y=60 \sin \left(5 x+1.5 \times 10^9 t\right) T$

$B_y=2 \times 10^{-7} \cos \left(5 x+1.5 \times 10^9 t\right) T$

$B_x=2 \times 10^{-7} \cos \left(5 x+1.5 \times 10^9 t\right) T$

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