AIPMT 2012 Mains | Electromagnetic Waves Question 20 | Physics

AIPMT 2012 Mains

MCQ (Single Correct Answer)

-1

The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagatting in vacuum is equal to

the speed of light in vacuum

reciprocal of speed of light in vacuum

the ratio of magnetic permeability to the electric susceptibility of vacuum

unity

AIPMT 2012 Prelims

MCQ (Single Correct Answer)

-1

The electric field associated with an em wave in vacuum is given by
E = $$\widehat i$$ 40 cos (kz $$-$$ 6 $$ \times $$ 10⁸ t) where E, z and t are in volt/m, meter and seconds respectively. The value of wave vector k is

2 m^$$-$$1

0.5 m^$$-$$1

6 m^$$-$$1

3 m^$$-$$1

AIPMT 2011 Prelims

MCQ (Single Correct Answer)

-1

The electric and the magnetic field, associated with an e.m. wave, propagating along the +z-axis, can be represented by

$$\left[ {\overrightarrow E = {E_0}\widehat i,\overrightarrow B = {B_0}\widehat j} \right]$$

$$\left[ {\overrightarrow E = {E_0}\widehat k,\overrightarrow B = {B_0}\widehat i} \right]$$

$$\left[ {\overrightarrow E = {E_0}\widehat j,\overrightarrow B = {B_0}\widehat i} \right]$$

$$\left[ {\overrightarrow E = {E_0}\widehat j,\overrightarrow B = {B_0}\widehat k} \right]$$

AIPMT 2011 Prelims

MCQ (Single Correct Answer)

-1

The decreasing order of wavelength of infrared, microwave, ultraviolet and gamma rays is

microwave, infrared, ultraviolet, gamma rays

gamma rays, ultraviolet, infraref, microwaves

microwaves, gamma rays, infrared, ultraviolet

infrared, microwave, ultraviolet, gamma rays

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