NEET 2022 Phase 2 | Electromagnetic Waves Question 5 | Physics

NEET 2022 Phase 2

MCQ (Single Correct Answer)

-1

The magnetic field of a plane electromagnetic wave is given by $$\overrightarrow B = 3 \times {10^{ - 8}}\cos (1.6 \times {10^3}x + 48 \times {10^{10}}t)\widehat j$$, then the associated electric field will be :

$$9\cos (1.6 \times {10^3}x + 48 \times {10^{10}}t)\widehat k$$ V/m

$$3 \times {10^{ - 8}}\cos (1.6 \times {10^3}x + 48 \times {10^{10}}t)\widehat i$$ V/m

$$3 \times {10^{ - 8}}\sin (1.6 \times {10^3}x + 48 \times {10^{10}}t)\widehat i$$ V/m

$$9\sin (1.6 \times {10^3}x - 48 \times {10^{10}}t)\widehat k$$ V/m

NEET 2022 Phase 2

MCQ (Single Correct Answer)

-1

The ratio of the magnitude of the magnetic field and electric field intensity of a plane electromagnetic wave in free space of permeability $${\mu _0}$$ and permittivity $${\varepsilon _0}$$ is (Given that c - velocity) of light in free space

$${{\sqrt {{\mu _0}{\varepsilon _0}} } \over c}$$

$${1 \over c}$$

$${c \over {\sqrt {{\mu _0}{\varepsilon _0}} }}$$

NEET 2022 Phase 1

MCQ (Single Correct Answer)

-1

Match List - I with List - II

	List - I (Electromagnetic waves)		List - II (Wavelength)
(a)	AM radio waves	(i)	$${10^{ - 10}}$$ m
(b)	Microwaves	(ii)	$${10^2}$$ m
(c)	Infrared radiations	(iii)	$${10^{ - 2}}$$ m
(d)	X-rays	(iv)	$${10^{ - 4}}$$ m

Choose the correct answer from the options given below

(a) - (iv), (b) - (iii), (c) - (ii), (d) - (i)

(a) - (iii), (b) - (ii), (c) - (i), (d) - (iv)

(a) - (iii), (b) - (iv), (c) - (ii), (d) - (i)

(a) - (ii), (b) - (iii), (c) - (iv), (d) - (i)

NEET 2022 Phase 1

MCQ (Single Correct Answer)

-1

When light propagates through a material medium of relative permittivity $$\varepsilon $$_r and relative permeability $$\mu$$_r, the velocity of light, v is given by (c-velocity of light in vacuum)

v = c

$$v = \sqrt {{{{\mu _r}} \over {{\varepsilon _r}}}} $$

$$v = \sqrt {{{{\varepsilon _r}} \over {{\mu _r}}}} $$

$$v = {c \over {\sqrt {{\varepsilon _r}{\mu _r}} }}$$

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