AIPMT 2010 Mains | Electromagnetic Waves Question 21 | Physics

AIPMT 2010 Mains

MCQ (Single Correct Answer)

-1

The electric field of an electromagnetic wave in free space is given by $$\overrightarrow E = 10\cos ({10^7}t + kx)\widehat j\,\,V/m,$$ where t and x are in seconds and metres respectively. It can be inferred that
(1)  the wavelength $$\lambda $$ is 188.4 m.
(2)  the wave number k is 0.33 rad/m.
(3)  the wave amplitude is 10 V/m.
(4)  the wave is propagating along +x direction.

Which one of the following pairs of statements is correct ?

(3) and (4)

(1) and (2)

(2) and (3)

(1) and (3)

AIPMT 2010 Prelims

MCQ (Single Correct Answer)

-1

Which of the following statement is false for the properties of electromagnetic waves ?

Both electric and magnetic field vectors attain the maxima and minima at the same place and same time.

The energy in electromagnetic wave is divided equally between electric and magnetic vectors.

Both electric and magnetic field vectors are parallel to each other and perpendicular to the direction of propagation of wave.

These waves do not require any material medium for propagation.

AIPMT 2009

MCQ (Single Correct Answer)

-1

The electric field part of an electromagnetic wave in a medium is represented by E_x = 0;

$${E_y} = 2.5{N \over C}\cos \left[ {\left( {2\pi \times {{10}^6}{{rad} \over m}} \right)t - \left( {\pi \times {{10}^{ - 2}}{{rad} \over s}} \right)x} \right];$$

E_z = 0.

moving along x direction with frequency 10⁶ Hz and wavelength 100 m.

moving along x direction with frequency 10⁶ Hz and wavelength 200 m.

moving along $$-$$x direction with frequency 10⁶ Hz and wavelength 200 m.

moving along y direction with frequency $$2\pi \times {10^6}\,Hz$$ and wavelength 200 m.

AIPMT 2008

MCQ (Single Correct Answer)

-1

The velocity of electromagnetic radiation in a medium of permittivity $$\varepsilon $$₀ and permeability $$\mu $$₀ is given by

$${1 \over {\sqrt {{\mu _0}{\varepsilon _0}} }}$$

$$\sqrt {{{{\mu _0}} \over {{\varepsilon _0}}}} $$

$$\sqrt {{{{\varepsilon _0}} \over {{\mu _0}}}} $$

$$\sqrt {{\mu _0}{\varepsilon _0}} $$