MHT CET 2026 11th April Morning Shift | Liquid Solution Question 44 | Chemistry

Vapour pressure of $\text{CCl}_4$ at $25^\circ$C is $143$ mm Hg. If $0.5$ g of a non-volatile solute is dissolved in $100 \text{ cm}^3$ of $\text{CCl}_4$. Find the vapour pressure of the solution.
(Density of $\text{CCl}_4 = 1.58 \text{ g}/\text{cm}^3$ and molecular weight of solute is $65$)

$141.93$ mm

$194.39$ mm

$199.34$ mm

$143.99$ mm

MHT CET 2026 11th April Morning Shift

MCQ (Single Correct Answer)

-0

The solubility of $\text{N}_2$ gas in water at $25^\circ$C and $1$ bar is $6.85 \times 10^{-4} \text{ mol L}^{-1}$. Calculate the solubility of $\text{N}_2$ gas in water at the same temperature when the partial pressure of $\text{N}_2$ is $0.70$ bar

$5.138 \times 10^{-4} \text{ mol L}^{-1}$

$5.480 \times 10^{-4} \text{ mol L}^{-1}$

$4.795 \times 10^{-4} \text{ mol L}^{-1}$

$4.875 \times 10^{-4} \text{ mol L}^{-1}$

MHT CET 2026 11th April Morning Shift

MCQ (Single Correct Answer)

-0

Identify from the following pair of solutions that exhibits the same osmotic pressure.
[molar mass of urea $= 60$ g mol$^{-1}$ and molar mass of glucose $= 180$ g mol$^{-1}$]

$6$ g/L urea solution and $18$ g/L glucose solution.

$12$ g/L urea solution and $18$ g/L glucose solution.

$18$ g/L urea solution and $18$ g/L glucose solution.

$6$ g/L urea solution and $6$ g/L glucose solution.

MHT CET 2025 5th May Evening Shift

MCQ (Single Correct Answer)

-0

Calculate the solubility of gas in solvent at $25^{\circ} \mathrm{C}$ and 0.8 atm if Henry's law constant for solvent is $6.8 \times 10^{-4} \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{~atm}^{-1}$.

$5.88 \times 10^{-4} \mathrm{M}$

$6.12 \times 10^{-4} \mathrm{M}$

$5.44 \times 10^{-4} \mathrm{M}$

$6.48 \times 10^{-4} \mathrm{M}$

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Some Basic Concepts of Chemistry Atomic Structure States of Matter Thermodynamics Chemical Equilibrium Ionic Equilibrium Liquid Solution Redox Reactions Surface Chemistry Solid State Electrochemistry Chemical Kinetics Nuclear Chemistry

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