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MHT CET 2019 2nd May Evening Shift
MCQ (More than One Correct Answer)
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The correct representation of Nernst's equation for half-cell reaction $\mathrm{Cu}^{2+}(\mathrm{aq})+\mathrm{e}^{-} \longrightarrow \mathrm{Cu}^{+}(\mathrm{aq})$ is

A
$E_{\mathrm{Cu}^{+}}^{\circ}, \mathrm{Cu}^{2+}=E_{\mathrm{Cu}^{+}}^{\circ}, \mathrm{Cu}^{2+}-\frac{0.0592}{2} \log \frac{\left[\mathrm{Cu}^{+}\right]}{\left[\mathrm{Cu}^{2+}\right]}$
B
$E_{\mathrm{Cu}^{+}, \mathrm{Cu}^{2+}}=E_{\mathrm{Cu}^{+}, \mathrm{Cu}^{2+}}^{\circ}-\frac{0.0592}{1} \log \frac{\left[\mathrm{Cu}^{+}\right]}{\left[\mathrm{Cu}^{2+}\right]}$
C
$E_{\mathrm{Cu}^{+}, \mathrm{Cu}^{2+}}=E_{\mathrm{Cu}^{+}, \mathrm{Cu}^{2+}}-\frac{0.0592}{2} \log \frac{\left[\mathrm{Cu}^{+}\right]}{\left[\mathrm{Cu}^{2+}\right]}$
D
$E_{\mathrm{Cu}^{+}, \mathrm{Cu}^{2+}}=E_{\mathrm{Cu}^{+}}^{\circ} ; \mathrm{Cu}^{2+}-\frac{0.0592}{1} \log \frac{\left[\mathrm{Cu}^{+}\right]}{\left[\mathrm{Cu}^{2+}\right]}$
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