1
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
The normal boiling point of Ethyl acetate is $77^\circ\text{C}$. A solution of non-volatile non-electrolyte solute in ethyl acetate boils at $78^\circ\text{C}$. $K_b$ for ethyl acetate is $2.77\ ^\circ\text{C kg mol}^{-1}$. What is the molality of the solution ?
A
$0.361\ \text{m}$
B
$0.052\ \text{m}$
C
$0.075\ \text{m}$
D
$0.25\ \text{m}$
2
MHT CET 2026 16th April Evening Shift
MCQ (Single Correct Answer)
+1
-0
18 g of glucose (molar mass = 180 g/mol) is dissolved in water to prepare 500 ml solution at $15^\circ\text{C}$. Calculate the osmotic pressure of the solution. [$R = 0.0821\ \text{L atm K}^{-1}\ \text{mol}^{-1}$]
A
$1.65\ \text{atm}$
B
$4.73\ \text{atm}$
C
$5.57\ \text{atm}$
D
$2.34\ \text{atm}$
3
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
For a binary solution, when a nonvolatile nonelectrolyte solute is dissolved in solvent, the vapour pressure of solvent decreases by 20 % . what is mole fraction of solvent in solution ?
A
$0.02$
B
$0.08$
C
$0.2$
D
$0.8$
4
MHT CET 2026 16th April Morning Shift
MCQ (Single Correct Answer)
+1
-0
Calculate the boiling point of an aqueous solution containing 18 g glucose in 100 g water if the molal elevation constant of water is $0.5\ \text{K kg mol}^{-1}$.
[Molar mass of glucose $= 180\ \text{g mol}^{-1}$ and boiling point of water $= 100\ ^\circ\text{C}$]
A
$100\ ^\circ\text{C}$
B
$100.5\ ^\circ\text{C}$
C
$101.0\ ^\circ\text{C}$
D
$101.5\ ^\circ\text{C}$

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