What is printed by the following ANSI C program?

#include <stdio.h>
int main(int argc, char *argv[ ]) {
   int x = 1, z[2] = {10, 11};
   int *p = NULL;
   p = &x;
   *p = 10;
   p = &z[1];
   *(&z[0] + 1) += 3;
   printf("%d, %d, %d\n", x, z[0], z[1]);
   return 0;
} 

Consider the following ANSI C program.

#include<stdio.h>

int main(){

int arr[4][5];

int i, j;

for(i =0; i<4; i++){

for (j =0; j<5; j++){

arr [i][j] = 10*i + j;

}

}

print("%d", *(arr[1] + 9));

return 0;

}

What is the output of the above program?

Consider the following C program :

#include < stdio.h >
 int main ()  {
            int arr [] = {1,2,3,4,5,6,7,8,9,0,1,2,5}, *ip = arr+4;
             printf ("%d\n", ip[1]);
             return 0;
}

The number that will be displayed on execution of the program is _______.

Consider the following C program.

#include< stdio.h >
struct Ournode{
 char x,y,z;
};
int main(){
 struct Ournode p = {'1', '0', 'a'+2};
 struct Ournode *q = &p;
 printf ("%c, %c", *((char*)q+1), *((char*)q+2));
 return 0;
}

The output of this program is: