1
GATE CSE 2019
Numerical
+2
-0.67
A relational database contains two tables Student and Performance as shown below:
GATE CSE 2019 Database Management System - Structured Query Language Question 5 English
The primary key of the Student table is Roll_no. For the Performance table, the columns Roll_no. and Subject_code together from the primary key. Consider the SQL query given below:

SELECT S.Student_name, sum (P.Marks)
       FROM Student S, Performance P
       WHERE P.Marks > 84
       GROUP BY S.Student_name;


The number of rows returned by the above SQL query is _____.
Your input ____
2
GATE CSE 2016 Set 2
Numerical
+2
-0
Consider the following database table named $$water$$_$$schemes :$$

water_schemes
scheme_no district_name capacity
1 Ajmer 20
1 Bikaner 10
2 Bikaner 10
3 Bikaner 20
1 Churu 10
2 Churu 20
1 Dungargarh 10

The number of tuples returned by the following $$SQL$$ query is _______________.

with total(name, capacity) as
    select district_name, sum(capacity)
    from water_schemes
    group by district_name
with total_avg(capacity) as
    select avg(capacity)
    from total
select name
    from total, total_avg
    where total.capacity ≥ total_avg.capacity
Your input ____
3
GATE CSE 2015 Set 1
Numerical
+2
-0

Consider the following relation:

Student

Roll_No Student_Name
1 Raj
2 Rohit
3 Raj

Performance

Roll_No Course Marks
1 Math 80
1 English 70
2 Math 75
3 English 80
2 Physics 65
3 Math 80

Consider the following SQL query.

SELECT S.Student_Name, Sum(P.Marks) 
FROM Student S, Performance P
WHERE S.Roll_No= P.Roll_No
GROUP BY S.STUDENT_Name
The numbers of rows that will be returned by the SQL query is___________.
Your input ____
4
GATE CSE 2014 Set 3
MCQ (Single Correct Answer)
+2
-0.6

Consider the following relational schema:

employee (empId, empName, empDept )

customer (custId, custName, salesRepId, rating)

SalesRepId is a foreign key referring to empId of the employee relation. Assume that each employee makes a sale to at least one customer. What does the following query return?
SELECT empName 
FROM employee E 
WHERE NOT EXISTS (SELECT custId 
       FROM customer C 
       WHERE C.salesRepId = E.empId 
       AND C.rating <> 'GOOD');
A
Names of all the employees with at least one of their customers having a 'GOOD' rating.
B
Names of all the employees with at most one of their customers having a 'GOOD' rating.
C
Names of all the employees with none of their customers having a 'GOOD' rating.
D
Names of all the employees with all their customers having a 'GOOD' rating.
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