Given a Context-Free Grammar G as follows :

$S \rightarrow A a|b a c| d c \mid b d a$

$A \rightarrow d$

Which ONE of the following statements is TRUE?

Consider two grammars $G_1$ and $G_2$ with the production rules given below:

$G_1: S \rightarrow$ if $E$ then $S \mid$ if $E$ then $S$ else $S \mid a$

$$\mathrm{E} \rightarrow \mathrm{~b}$$

$G_2: S \rightarrow$ if $E$ then $S \mid M$

$E \rightarrow$ if $E$ then $M$ else $S \mid c$

$$\mathrm{E} \rightarrow \mathrm{~b}$$

where if, then, else, $a, b, c$ are the terminals.

Which of the following option(s) is/are CORRECT?

Which of the following statement(s) is/are TRUE while computing First and Follow during top down parsing by a compiler?

Consider the following context-free grammar where the start symbol is S and the set of terminals is {a,b,c,d}.

$ S \rightarrow AaAb \mid BbBa $

$ A \rightarrow cS \mid \epsilon $

$ B \rightarrow dS \mid \epsilon $

The following is a partially-filled LL(1) parsing table.

Which one of the following options represents the CORRECT combination for the numbered cells in the parsing table?

Note: In the options, “blank” denotes that the corresponding cell is empty.