1
GATE ECE 1989
MCQ (Single Correct Answer)
+2
-0.6
The feedback amplifier shown in Fig.has: GATE ECE 1989 Analog Circuits - Feedback Amplifier Question 3 English
A
current - series feedback with large input impedance and large output impedance.
B
voltage - series feedback with large input impedance and low output impedance.
C
voltage - shunt feedback with low input impedance and low output impedance.
D
current - shunt feedback with low input impedance and output impedance.
2
GATE ECE 1989
MCQ (Single Correct Answer)
+2
-0.6
Refer to Fig. GATE ECE 1989 Analog Circuits - Operational Amplifier Question 32 English
A
For $${V_i} > 0,\,\,{V_0}\, = - {{{R_2}} \over {{R_1}}}{V_i}$$
B
For $${V_i} > 0,\,\,{V_0}\, = 0.$$
C
For $${V_i} < 0,\,\,{V_0}\, = - {{{R_2}} \over {{R_1}}}{V_i}$$
D
For $${V_i} < 0,\,\,{V_0}\, = 0.$$
3
GATE ECE 1989
MCQ (Single Correct Answer)
+2
-0.6
Of the four biasing circuits shown in Fig. For a BJT, indicate the one which can have maximum bias stability:
A
GATE ECE 1989 Analog Circuits - Bipolar Junction Transistor Question 9 English Option 1
B
GATE ECE 1989 Analog Circuits - Bipolar Junction Transistor Question 9 English Option 2
C
GATE ECE 1989 Analog Circuits - Bipolar Junction Transistor Question 9 English Option 3
D
GATE ECE 1989 Analog Circuits - Bipolar Junction Transistor Question 9 English Option 4
4
GATE ECE 1989
MCQ (Single Correct Answer)
+2
-0.6
A source produces 4 symbols with probabilities $${1 \over 2},\,{1 \over 4},\,{1 \over 8}\,\,and\,\,{1 \over 8}.$$ For this source, a practical coding scheme has an average codeword lenght of 2 bits/symbols. The efficiency of the code is :
A
1
B
7/8
C
1/2
D
1/4