1
GATE ECE 1988
MCQ (Single Correct Answer)
+2
-0.6
The transistor in the amplifier shown below has following parameters: $$${h_{fe}}\, = \,100,\,{h_{ie}}\, = \,2k\Omega ,\,{h_{re}}\, = \,0,$$$ $${h_{oe}}\, = \,0.05\,\,m\Omega .\,\,C$$ is very large.

The output impedance is

GATE ECE 1988 Analog Circuits - Bipolar Junction Transistor Question 27 English
A
$$20k\Omega .$$
B
$$16k\Omega .$$
C
$$5k\Omega .$$
D
$$4k\Omega .$$
2
GATE ECE 1988
MCQ (Single Correct Answer)
+2
-0.6
Each transistor in the Darlington pair (see Fig. below) has hfe = 100. The overall hfe of the composite transistor neglecting the leakage current is GATE ECE 1988 Analog Circuits - Bipolar Junction Transistor Question 53 English
A
1000
B
10001
C
10100
D
10200
3
GATE ECE 1988
MCQ (Single Correct Answer)
+2
-0.6
The quiescent collector current Ic, of a transistor is increased by changing resistance. As a result
A
gm will not be affected
B
gm will decrease
C
gm will increase
D
gm will increase or decrease depending upon bias stability.
4
GATE ECE 1988
MCQ (Single Correct Answer)
+2
-0.6
The OP-AMP shown in fig. below is ideal. $$R\, = \,\sqrt {L/C.} $$ The phase angle between V0 and Vi at $$\omega = 1/\sqrt {LC} $$ is GATE ECE 1988 Analog Circuits - Operational Amplifier Question 33 English
A
$$\pi /2$$
B
$$\pi $$
C
$$3\pi /2$$
D
$$2\pi $$