1
GATE ECE 1988
MCQ (Single Correct Answer)
+2
-0.6
Consider a closed-loop system shown in fig. (a) below. The root locus for it is shown in fig. (b). The closed-loop transfer function for the system is GATE ECE 1988 Control Systems - Root Locus Diagram Question 5 English
A
$$\frac K{1+\left(0.5s+1\right)\left(10s+1\right)}$$
B
$$\frac K{\left(s+2\right)\left(s+0.1\right)}$$
C
$$\frac K{1+K\left(0.5s+1\right)\left(10s+1\right)}$$
D
$$\frac K{K+0.2\left(0.5s+1\right)\left(10s+1\right)}$$
2
GATE ECE 1988
MCQ (Single Correct Answer)
+1
-0.3
Minimum number of 2-input NAND gates required to implement the function, f=($$\overline X $$+$$\overline Y $$)(Z+W) is
A
3
B
4
C
5
D
6
3
GATE ECE 1988
MCQ (Single Correct Answer)
+1
-0.3
For the circuit shown below the output Fis given by GATE ECE 1988 Digital Circuits - Logic Gates Question 31 English
A
F=1
B
F=0
C
F=X
D
F= $$\overline X $$
4
GATE ECE 1988
MCQ (Single Correct Answer)
+1
-0.3
The minimum number of 2-input NAND gates required to implement the Boolean function Z=A$$\overline {B\,} $$C, assuming that A, B and C are available, is
A
two
B
three
C
five
D
six
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