When a bio-chemical reaction is carried out in laboratory, outside the human body in absence of enzyme, then rate of reaction obtained is 10$$-$$6 times, the activation energy of reaction in the presence of enzyme is
A
6/RT
B
P is required
C
different from E$$a$$ obtained in laboratory
D
can't say anything.
Explanation
From Arrhenius equation, k = Ae
–Ea/RT
The activation energy of the reaction in the
presence of enzyme is different from Ea obtained in
laboratory.
2
AIPMT 2000
MCQ (Single Correct Answer)
For the reaction H+ + BrO$$_3^ - $$ + 3Br$$-$$ $$ \to $$ 5Br2 + H2O
which of the following relation correctly represents the consumption and formation of products.
Enzymes act like catalyst in biochemical
reactions. Presence of an enzyme increases the rate
of reaction by lowering the activation energy of the
reactant.
Questions Asked from Chemical Kinetics
On those following papers in MCQ (Single Correct Answer)
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