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1

AIPMT 2010 Mains

MCQ (Single Correct Answer)
The rate of the reaction, 2NO + Cl2 $$ \to $$ 2NOCl is given by the rate equation rate = k[NO]2[Cl2]. The value of the rate constant can be increased by
A
increasing the temperature
B
increasing the concentration of NO
C
increasing the concentration of the Cl2
D
doing all of these.

Explanation

The value of rate constant can be increased by increasing the temperature and is independent of the initial concerntration of the reactants.
2

AIPMT 2010 Prelims

MCQ (Single Correct Answer)
For the reaction N2O5(g) $$ \to $$  2NO2(g) + 1/2O2(g)
the value of rate of disappearance of N2O5 is given as 6.25 $$ \times $$ 10$$-$$3 mol L$$-$$1 s$$-$$1. The rate of formation of NO2 and O2 is given respectively as
A
6.25 $$ \times $$ 10$$-$$3 mol L$$-$$1 s$$-$$1 and
6.25 $$ \times $$ 10$$-$$3 mol L$$-$$1 s$$-$$1
B
1.25 $$ \times $$ 10$$-$$2 mol L$$-$$1 s$$-$$1 and
3.125 $$ \times $$ 10$$-$$3 mol L$$-$$1 s$$-$$1
C
6.25 $$ \times $$ 10$$-$$3 mol L$$-$$1 s$$-$$1 and
3.125 $$ \times $$ 10$$-$$3 mol L$$-$$1 s$$-$$1
D
1.25 $$ \times $$ 10$$-$$2 mol L$$-$$1 s$$-$$1 and
6.25 $$ \times $$ 10$$-$$3 mol L$$-$$1 s$$-$$1

Explanation

N2O5(g) $$ \to $$  2NO2(g) + 1/2O2(g)

$$ - {{d\left[ {{N_2}{O_5}} \right]} \over {dt}} = {1 \over 2}{{d\left[ {N{O_2}} \right]} \over {dt}} = 2{{d\left[ {{O_2}} \right]} \over {dt}}$$

$$ \Rightarrow $$ $${{d\left[ {N{O_2}} \right]} \over {dt}} = - 2{{d\left[ {{N_2}{O_5}} \right]} \over {dt}}$$

= 2 $$ \times $$ 6.25 $$ \times $$ 10 mol l-1 sec-1

= 1.25 $$ \times $$ 10$$-$$2 mol L$$-$$1 s$$-$$1

$${{d\left[ {{O_2}} \right]} \over {dt}} = - {1 \over 2}{{d\left[ {{N_2}{O_5}} \right]} \over {dt}}$$

= $${{6.25 \times {{10}^{ - 3}}} \over 2}$$

= 3.125 $$ \times $$ 10$$-$$3 mol L$$-$$1 s$$-$$1
3

AIPMT 2009

MCQ (Single Correct Answer)
Half-life period of a first order reaction is 1386 seconds. The specific rate constant of the reaction is
A
0.5 $$ \times $$ 10$$-$$2 s$$-$$1
B
0.5 $$ \times $$ 10$$-$$3 s$$-$$1
C
5.0 $$ \times $$ 10$$-$$2 s$$-$$1
D
5.0 $$ \times $$ 10$$-$$3 s$$-$$1.

Explanation

Specific rate constant

k = $${{0.693} \over {{t_{1/2}}}}$$

= $${{0.693} \over {1386}}$$

= 0.5 $$ \times $$ 10-3 sec-1
4

AIPMT 2009

MCQ (Single Correct Answer)
For the reaction A + B $$ \to $$ products, it is observed that

(i)  on doubling the initial concentration of A only, the rate of reaction is also doubled and
(ii)  on doubling the initial concentration of both A and B, there is a change by a factor of 8 in the rate of the reaction.

The rate of this reaction is given by
A
rate = k[A]2 [B]2
B
rate = k[A] [B]2
C
rate = k[A] [B]
D
rate = k[A]2 [B]

Explanation

R = k[A]m[B]n ... (i)

2R = k[2A]m[B]n ... (ii)

8R = k[2A]m[2B]n ... (iii)

from (i), (ii) and (iii), m = 1, n = 2

So, rate = k[A][B]2

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