AIPMT 2012 Prelims | Motion in a Straight Line Question 15 | Physics

AIPMT 2012 Prelims

MCQ (Single Correct Answer)

-1

The motion of a particle along a straight line is described by equation x = 8 + 12t $$-$$ t³ where x is in metre and t in second. The retardation of the particle when its velocity becomes zero is

24 m s^$$-$$2

zero

6 m s^$$-$$2

12 m s^$$-$$2

AIPMT 2011 Mains

MCQ (Single Correct Answer)

-1

A particle covers half of its total distance with speed v₁ and the rest half distance with speed v₂. Its average speed during the complete journey is

$${{{v_1} + {v_2}} \over 2}$$

$${{{v_1}{v_2}} \over {{v_1} + {v_2}}}$$

$${{2{v_1}{v_2}} \over {{v_1} + {v_2}}}$$

$${{v_1^2v_2^2} \over {v_1^2 + v_2^2}}$$

AIPMT 2011 Prelims

MCQ (Single Correct Answer)

-1

A boy standing at the top of a tower of 20 m height drops a stone. Assuming g = 10 m s^$$-$$2, the velocity with which it hits the ground is

10.0 m/s

20.0 m/s

40.0 m/s

5.0 m/s

AIPMT 2010 Prelims

MCQ (Single Correct Answer)

-1

A particle moves a distance x in time t according to equation x = (t + 5)^$$-$$1. The acceleration of particle is proportional to

(velocity)^3/2

(distance)²

(distance)^$$-$$2

(velocity)^2/3

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