NEET 2016 Phase 1 | Motion in a Straight Line Question 13 | Physics

NEET 2016 Phase 1

MCQ (Single Correct Answer)

-1

If the velocity of a particle is v = At + Bt², where A and B are constants, then the distance travelled by it between 1 s and 2 s is

$${3 \over 2}A + {7 \over 3}B$$

$${A \over 2} + {B \over 3}$$

$${3 \over 2}A + 4B$$

$$3A + 7B$$

AIPMT 2015 Cancelled Paper

MCQ (Single Correct Answer)

-1

A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to $$v\left( x \right) = \beta {x^{ - 2n}}$$, where $$\beta $$ and n are constants and x is the position of the particle. The acceleration of the particle as a function of x, is given by

$$ - 2{\beta ^2}{x^{ - 2n + 1}}$$

$$ - 2n{\beta ^2}{e^{ - 4n + 1}}$$

$$ - 2n{\beta ^2}{x^{ - 2n - 1}}$$

$$ - 2n{\beta ^2}{x^{ - 4n - 1}}$$

NEET 2013 (Karnataka)

MCQ (Single Correct Answer)

-1

The displacement 'x' (in meter) of a particle of mass 'm' (in kg) moving in one dimension under the action of a force, is related to time 't' (in sec) by t = $$\sqrt x + 3$$. The displacement of the particle when its velocity is zero, will be

4 m

0 m (zero)

6 m

2 m

NEET 2013

MCQ (Single Correct Answer)

-1

A stone falls freely under gravity. It covers distances h₁, h₂ and h₃ in the first 5 seconds, the next 5 seconds and the next 5 seconds respectively. The relation between h₁, h₂ and h₃ is

h₂ = 3h₁ and h₃ = 3h₂

h₁ = h₂ = h₃

h₁ = 2h₂ = 3h₃

$${h_1}$$ = $${{{h_2}} \over 3}$$ = $${{{h_3}} \over 5}$$

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Human Health and Diseases Body Fluids and Its Circulation Locomotion and Movement Neural Control and Coordination Reproduction in Organisms Reproductive Health Structural Organisation in Animals Digestion and Absorption Excretory Products and Their Elimination Chemical Coordination and Integration Human Reproduction Animal Kingdom Breathing and Exchange of Gases Evolution