1
NEET 2013 (Karnataka)
MCQ (Single Correct Answer)
+4
-1
Change Language
The displacement 'x' (in meter) of a particle of mass 'm' (in kg) moving in one dimension under the action of a force, is related to time 't' (in sec) by t = $$\sqrt x + 3$$. The displacement of the particle when its velocity is zero, will be
A
4 m
B
0 m (zero)
C
6 m
D
2 m
2
NEET 2013
MCQ (Single Correct Answer)
+4
-1
Change Language
A stone falls freely under gravity. It covers distances h1, h2 and h3 in the first 5 seconds, the next 5 seconds and the next 5 seconds respectively. The relation between h1, h2 and h3 is
A
h2 = 3h1 and h3 = 3h2
B
h1 = h2 = h3
C
h1 = 2h2 = 3h3
D
$${h_1}$$ = $${{{h_2}} \over 3}$$ = $${{{h_3}} \over 5}$$
3
AIPMT 2012 Prelims
MCQ (Single Correct Answer)
+4
-1
Change Language
The motion of a particle along a straight line is described by equation x = 8 + 12t $$-$$ t3 where x is in metre and t in second. The retardation of the particle when its velocity becomes zero is
A
24 m s$$-$$2
B
zero
C
6 m s$$-$$2
D
12 m s$$-$$2
4
AIPMT 2011 Mains
MCQ (Single Correct Answer)
+4
-1
A particle covers half of its total distance with speed v1 and the rest half distance with speed v2. Its average speed during the complete journey is
A
$${{{v_1} + {v_2}} \over 2}$$
B
$${{{v_1}{v_2}} \over {{v_1} + {v_2}}}$$
C
$${{2{v_1}{v_2}} \over {{v_1} + {v_2}}}$$
D
$${{v_1^2v_2^2} \over {v_1^2 + v_2^2}}$$
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