AIPMT 2012 Prelims | Motion in a Plane Question 25 | Physics

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AIPMT 2012 Prelims

MCQ (Single Correct Answer)

-1

The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is

$$\theta $$ = tan^$$-$$1$$\left( {{1 \over 4}} \right)$$

$$\theta $$ = tan^$$-$$1(4)

$$\theta $$ = tan^$$-$$1(2)

$$\theta $$ = 45^o

AIPMT 2011 Mains

MCQ (Single Correct Answer)

-1

A projectile is fired at an angle of 45^o with the horizontal. Elevation angle of the projectile at its highest point as seen from the point of projection, is

45^o

60^o

tan^$$-$$1 $$\left( {{1 \over 2}} \right)$$

tan^$$-$$1 $$\left( {{{\sqrt 3 } \over 2}} \right)$$

AIPMT 2011 Prelims

MCQ (Single Correct Answer)

-1

A body is moving with velocity 30 m/s towards east . After 10 seconds its velocity becomes 40 m/s towards north. The average acceleration of the body is

1 m/s²

7 m/s²

$$\sqrt 7 $$ m/s²

5 m/s²

AIPMT 2011 Prelims

MCQ (Single Correct Answer)

-1

A missile is fired for maximum range with an initial velocity of 20 m/s. If g = 10 m/s², the range of the missile is

40 m

50 m

60 m

20 m

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