1
NEET 2021
MCQ (Single Correct Answer)
+4
-1
A particle moving in a circle of radius R with a uniform speed takes a time T to complete one revolution.

If this particle were projected with the same speed at an angle '$$\theta$$' to the horizontal, the maximum height attained by it equals 4R. The angle of projection, $$\theta$$, is then given by :
A
$$\theta = {\sin ^{ - 1}}{\left( {{{2g{T^2}} \over {{\pi ^2}R}}} \right)^{1/2}}$$
B
$$\theta = {\cos ^{ - 1}}{\left( {{{g{T^2}} \over {{\pi ^2}R}}} \right)^{1/2}}$$
C
$$\theta = {\cos ^{ - 1}}{\left( {{{{\pi ^2}R} \over {g{T^2}}}} \right)^{1/2}}$$
D
$$\theta = {\sin ^{ - 1}}{\left( {{{{\pi ^2}R} \over {g{T^2}}}} \right)^{1/2}}$$
2
NEET 2021
MCQ (Single Correct Answer)
+4
-1
A car starts from rest and accelerates at 5m/s2. At t = 4 s, a ball is dropped out of a window by a person sitting in the car. What is the velocity and acceleration of the ball at t = 6 s? (Take g = 10 m/s2)
A
20$$\sqrt 2 $$ m/s, 10 m/s2
B
20 m/s, 5 m/s2
C
20 m/s, 0
D
20$$\sqrt 2 $$ m/s, 0
3
NEET 2019
MCQ (Single Correct Answer)
+4
-1
When an object is shot from the bottom of a long smooth inclined plane kept at an angle 60o with horizontal, it can travel a distance x1 along the plane. But when the inclination is decreased to 30o and the same object is shot with the same velocity, it can travel x2 distance. Then x1 : x2 will be :
A
1 : $$\sqrt 2 $$
B
$$\sqrt 2 $$ : 1
C
1 : $$\sqrt 3 $$
D
1 : 2$$\sqrt 3 $$
4
NEET 2019
MCQ (Single Correct Answer)
+4
-1
A particle moving with velocity $$\overrightarrow V $$ is acted by three forces shown by the vector triangle PQR. The velocity of the particle will : NEET 2019 Physics - Motion in a Plane Question 9 English
A
remain constant
B
increase
C
decrease
D
change according to the smallest force $$\overrightarrow {QR} $$
NEET Subjects
EXAM MAP
Medical
NEET
Graduate Aptitude Test in Engineering
GATE CSEGATE ECEGATE EEGATE MEGATE CEGATE PIGATE IN
Civil Services
UPSC Civil Service
Defence
NDA
CBSE
Class 12