NEET 2022 Phase 2 | Motion in a Plane Question 5 | Physics

A cricket ball is thrown by a player at a speed of 20 m/s in a direction 30$$^\circ$$ above the horizontal. The maximum height attained by the ball during its motion is

(g = 10 m/s²)

25 m

5 m

10 m

20 m

NEET 2022 Phase 1

MCQ (Single Correct Answer)

-1

A ball is projected with a velocity, 10 ms^$$-$$1, at an angle of 60$$^\circ$$ with the vertical direction. Its speed at the highest point of its trajectory will be

Zero

5$$\sqrt3$$ ms^$$-$$1

5 ms^$$-$$1

10 ms^$$-$$1

NEET 2021

MCQ (Single Correct Answer)

-1

A particle moving in a circle of radius R with a uniform speed takes a time T to complete one revolution.

If this particle were projected with the same speed at an angle '$$\theta$$' to the horizontal, the maximum height attained by it equals 4R. The angle of projection, $$\theta$$, is then given by :

$$\theta = {\sin ^{ - 1}}{\left( {{{2g{T^2}} \over {{\pi ^2}R}}} \right)^{1/2}}$$

$$\theta = {\cos ^{ - 1}}{\left( {{{g{T^2}} \over {{\pi ^2}R}}} \right)^{1/2}}$$

$$\theta = {\cos ^{ - 1}}{\left( {{{{\pi ^2}R} \over {g{T^2}}}} \right)^{1/2}}$$

$$\theta = {\sin ^{ - 1}}{\left( {{{{\pi ^2}R} \over {g{T^2}}}} \right)^{1/2}}$$

NEET 2021

MCQ (Single Correct Answer)

-1

A car starts from rest and accelerates at 5m/s². At t = 4 s, a ball is dropped out of a window by a person sitting in the car. What is the velocity and acceleration of the ball at t = 6 s? (Take g = 10 m/s²)

20$$\sqrt 2 $$ m/s, 10 m/s²

20 m/s, 5 m/s²

20 m/s, 0

20$$\sqrt 2 $$ m/s, 0

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