AIPMT 2006 | Motion in a Plane Question 37 | Physics

AIPMT 2006

MCQ (Single Correct Answer)

-1

For angles of projection of a projectile at angle (45^o $$-$$ $$\theta $$) and (45^o + $$\theta $$), the horizontal range described by the projectile are in the ratio of

2 : 1

1 : 1

2 : 3

1 : 2.

AIPMT 2006

MCQ (Single Correct Answer)

-1

The vectors $$\overrightarrow A $$ and $$\overrightarrow B $$ are such that $$\left| {\overrightarrow A + \overrightarrow B } \right| = \left| {\overrightarrow A - \overrightarrow B } \right|.$$ The angle between the two vectors is

45^o

90^o

60^o

75^o

AIPMT 2005

MCQ (Single Correct Answer)

-1

Two boys are standing at the ends A and B of a ground where AB = a. The boy at B starts running in a direction perpendicular to AB with velocity v₁. The boy at A starts running simultaneously with velocity v and catches the other in a time t, where t is

$${a \over {\sqrt {{v^2} + {v_1}^2} }}$$

$${a \over {v + {v_1}}}$$

$${a \over {v - {v_1}}}$$

$$\sqrt {{a \over {{v^2} - {v_1}^2}}} $$

AIPMT 2005

MCQ (Single Correct Answer)

-1

If the angle between the vectors $$\overrightarrow A $$ and $$\overrightarrow B $$ is $$\theta $$, the value of the product $$\left( {\overrightarrow B \times \overrightarrow A } \right).\overrightarrow A $$ is equal to

BA²sin$$\theta $$

BA²cos$$\theta $$

BA²sin$$\theta $$cos$$\theta $$

zero.

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