Rate constants of a reaction at $$500 \mathrm{~K}$$ and $$700 \mathrm{~K}$$ are $$0.04 \mathrm{~s}^{-1}$$ and $$0.14 \mathrm{~s}^{-1}$$, respectively; then, activation energy of the reaction is :

(Given: $$\log 3.5=0.5441, \mathrm{R}=8.31 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}$$)

Activation energy of any chemical reaction can be calculated if one knows the value of

Which plot of $$\ln \mathrm{k}$$ vs $$\frac{1}{\mathrm{~T}}$$ is consistent with Arrhenius equation?

The rate of a reaction quadruples when temperature changes from $$27^{\circ} \mathrm{C}$$ to $$57^{\circ} \mathrm{C}$$. Calculate the energy of activation.

Given $$\mathrm{R}=8.314 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}, \log 4=0.6021$$