At a given temperature and pressure, the equilibrium constant values for the equilibria are given below:

$$\begin{aligned} & 3 \mathrm{~A}_2+\mathrm{B}_2 \rightleftharpoons 2 \mathrm{~A}_3 \mathrm{~B}, \mathrm{~K}_1 \\ & \mathrm{~A}_3 \mathrm{~B} \rightleftharpoons \frac{3}{2} \mathrm{~A}_2+\frac{1}{2} \mathrm{~B}_2, \mathrm{~K}_2 \end{aligned}$$

The relation between $$\mathrm{K}_1$$ and $$\mathrm{K}_2$$ is :

For the reaction in equilibrium

$$\mathrm{N}_2(\mathrm{~g})+3 \mathrm{H}_2(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_3(\mathrm{~g}), \Delta \mathrm{H}=-\mathrm{Q}$$

Reaction is favoured in forward direction by:

In which of the following equilibria, $$\mathrm{K}_p$$ and $$\mathrm{K}_{\mathrm{c}}$$ are NOT equal?

For the reaction $$2 \mathrm{~A} \rightleftharpoons \mathrm{B}+\mathrm{C}, \mathrm{K}_{\mathrm{c}}=4 \times 10^{-3}$$. At a given time, the composition of reaction mixture is: $$[A]=[B]=[C]=2 \times 10^{-3} \mathrm{M} \text {. }$$ Then, which of the following is correct?