For a reaction between A and B the order with respect to A is 2 and the other with respect to B is 3. The concentrations of both A and B are doubled, the rate will increase by a factor of

What is the activation energy for a reaction if its rate doubles when the temperature is raised from 20^oC to 35^oC?
(R = 8.314 J mol^$$-$$1 K^$$-$$1)

In a zero-order reaction, for every 10^oC rise of temperature, the rate is doubled. If the temperature is increased from 10^oC to 100^oC, the rate of the reaction will become

In a reaction, A + B $$ \to $$ product, rate is doubled when the concentration of B is doubled, and rate increases by a factor of 8 when the concentration of both the reactants (A and B) are doubled, rate law for the reaction can be written as