1
GATE EE 2002
Subjective
+5
-0
A single input single output system with $$y$$ as output and $$u$$ as input, is described by $$${{{d^2}y} \over {d{t^2}}} + 2{{dy} \over {dt}} + 10y = 5{{d\,u} \over {dt}} - 3\,u$$$
For the above system find an input $$u(t),$$ with zero initial condition, that produces the same output as with no input and with the initial conditions.
$${{d\,y\left( {{0^ - }} \right)} \over {dt}} = - 4,\,\,\,y\left( {{0^ - }} \right) = 1$$
2
GATE EE 2002
MCQ (Single Correct Answer)
+1
-0.3
$$s(t)$$ is step response and $$h(t)$$ is impulse response of a system. Its response $$y(t)$$ for any input $$u(t)$$ is given by
A
$${d \over {d\,t}}\int\limits_0^t s \left( {t - \tau } \right)\,u\left( \tau \right)\,d\,\tau $$
B
$$\int\limits_0^t s \left( {t - \tau } \right)\,u\left( \tau \right)\,d\,\tau $$
C
$$\int\limits_0^t {\int\limits_0^\tau s \left( {t - {\tau _1}} \right)\,u\left( {{\tau _1}} \right)\,d{\tau _1}} \,d\tau $$
D
$${d \over {d\,t}}\int\limits_0^t h \left( {t - \tau } \right)\,u\left( \tau \right)\,d\,\tau $$
3
GATE EE 2002
MCQ (Single Correct Answer)
+1
-0.3
Let Y(s) be the Laplace transformation of the function y(t), then the final value of the function is
A
$$\underset{s\rightarrow0}{L\mathrm{im}\;}Y\left(s\right)$$
B
$$\underset{s\rightarrow\infty}{L\mathrm{im}\;}Y\left(s\right)$$
C
$$\underset{s\rightarrow0}{L\mathrm{im}\;}sY\left(s\right)$$
D
$$\underset{s\rightarrow\infty}{L\mathrm{im}\;}sY\left(s\right)$$
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