1
GATE ECE 2009
+2
-0.6
A small signal source Vi(t) = A cos 20t + B sin 106 t, is applied to a transistor Amplifier as shown in fig. The transistor has $$\beta$$ = 150 and hie = 3k$$\Omega$$ , which expression best approximates $${V_0}\left( t \right)$$ ?
A
$$V_o\left( t \right)\,\, = \, - 1500\,\left( {{\rm A}\,\cos 20t\, + b\sin \,{{10}^6}t} \right)$$
B
$${V_o}\,\left( t \right)\,\, = \, - 1500\,\left( {{\rm A}\,\cos 20t\, + b\sin \,{{10}^6}t} \right)$$
C
$${V_o}\left( t \right)\,\, = \, - 1500\,B\sin \,{10^6}t$$
D
$${V_o}\left( t \right)\,\, = \, - 150\,B\sin \,{10^6}t$$
2
GATE ECE 2009
+2
-0.6
A communication channel with AWGN operating at a signal to noise ratio SNR > > 1 and band width B has capacity $${{C_1}}$$ . If the SNR is doubled keeping B constant, the resulting capacity $${{C_2}}$$ is given
A
$${C_2}\, \approx \,2\,{C_1}\,$$
B
$${C_2}\, \approx \,{C_1}\, + \,B$$
C
$${C_2}\, \approx \,{C_1}\, + \,2B$$
D
$${C_2}\, \approx \,{C_1}\, + \,0.3B$$
3
GATE ECE 2009
+2
-0.6
The amplitude of random signal is uniformly distributed between $$-$$5V and 5V

If the signal to quantization noise ratio required in uniformly quantizing the signals is 43.5 dB, the step size of the quantization is approximately

A
0.0333 V
B
0.05 V
C
0.0667 V
D
0.10 V
4
GATE ECE 2009
+2
-0.6
The amplitude of random signal is uniformly distributed between $$-$$5V and 5V

If the positive values of the signal are uniformly quantized with a step size of 0.05 V, and the negative values are uniformly quantized with a step size of 0.1V, the resulting signal to quantization noise ratio is approximately

A
46 dB
B
43.8 dB
C
42 dB
D
40 dB
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