1
GATE ECE 2009
MCQ (Single Correct Answer)
+2
-0.6
An AC source of RMS voltage $$20$$ $$V$$ with internal impedance $${Z_s} = \left( {1 + 2j} \right)\Omega $$ feeds a load of impedance $${Z_L} = \left( {7 + 4j} \right)\Omega $$ in the figure below. The reactive power consumed by the load is GATE ECE 2009 Network Theory - Sinusoidal Steady State Response Question 26 English
A
$$8$$ VAR
B
$$16$$ VAR
C
$$28$$ VAR
D
$$32$$ VAR
2
GATE ECE 2009
MCQ (Single Correct Answer)
+2
-0.6
In the circuit shown, what value of RL maximizes the power delivered to RL? GATE ECE 2009 Network Theory - Network Theorems Question 22 English
A
$$2.4\Omega$$
B
$$\frac8{3}\Omega$$
C
$$4\Omega$$
D
$$6\Omega$$
3
GATE ECE 2009
MCQ (Single Correct Answer)
+2
-0.6
The time domain behavior of an RL circuit is represented by $$$\mathrm L\frac{\mathrm{di}\left(\mathrm t\right)}{\mathrm{dt}}+\mathrm{Ri}\;=\;{\mathrm V}_0\left(1\;+\;\mathrm{Be}^{-\mathrm{Rt}/\mathrm L}\;\sin\;\mathrm t\right)\mathrm u\left(\mathrm t\right)$$$ For an initial current of i(0) = $$\frac{{\mathrm V}_0}{\mathrm R}$$, the steady state value of the current is given by
A
$$\mathrm i\left(\mathrm t\right)\rightarrow\frac{{\mathrm V}_0}{\mathrm R}$$
B
$$\mathrm i\left(\mathrm t\right)\rightarrow\frac{2{\mathrm V}_0}{\mathrm R}$$
C
$$\mathrm i\left(\mathrm t\right)\rightarrow\frac{{\mathrm V}_0}{\mathrm R}\left(1+\mathrm B\right)$$
D
$$\mathrm i\left(\mathrm t\right)\rightarrow\frac{2{\mathrm V}_0}{\mathrm R}\left(1+\mathrm B\right)$$
4
GATE ECE 2009
MCQ (Single Correct Answer)
+2
-0.6
The switch in the circuit shown was on position ‘a’ for a long time and is moved to position ‘b’ at time t = 0. The current i(t) for t > 0 is given by GATE ECE 2009 Network Theory - Transient Response Question 22 English
A
0.2e-125t u(t) mA
B
20e-1250t u(t) mA
C
0.2e-1250t u(t) mA
D
20e-1000t u(t) mA
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