AIPMT 2005 | Motion in a Plane Question 42 | Physics

AIPMT 2005

MCQ (Single Correct Answer)

-1

Two boys are standing at the ends A and B of a ground where AB = a. The boy at B starts running in a direction perpendicular to AB with velocity v₁. The boy at A starts running simultaneously with velocity v and catches the other in a time t, where t is

$${a \over {\sqrt {{v^2} + {v_1}^2} }}$$

$${a \over {v + {v_1}}}$$

$${a \over {v - {v_1}}}$$

$$\sqrt {{a \over {{v^2} - {v_1}^2}}} $$

AIPMT 2004

MCQ (Single Correct Answer)

-1

If $$\left| {\overrightarrow A \times \overrightarrow B } \right| = \sqrt 3 \overrightarrow A .\overrightarrow B $$ then the value of $$\left| {\overrightarrow A + \overrightarrow B } \right|$$ is

(A² + b² + AB)^1/2

$${\left( {{A^2} + {B^2} + {{AB} \over {\sqrt 3 }}} \right)^{1/2}}$$

A + B

(A² + B² + $${\sqrt 3 }$$AB)^1/2.

AIPMT 2003

MCQ (Single Correct Answer)

-1

The vector sum of two forces is perpendicular to their vector differences. In that case, the forces

are equal to each other

are equal to each other in magnitude

are not equal to each other in magnitude

cannot be predicted.

AIPMT 2002

MCQ (Single Correct Answer)

-1

A particle A is dropped from a height and another particle B is projected in horizontal direction with speed of 5/sec from the same height then correct statement is

particle A will reach at ground first with respect to particle B

particle B will reach at ground first with respect to particle A

both particles will reach at ground simultaneously

both particles will reach at ground with same speed.

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