1
MCQ (Single Correct Answer)

NEET 2013 (Karnataka)

The values of Ksp of CaCO3 and CaC2O4 are 4.7 $$ \times $$ 10$$-$$9 and 1.3 $$ \times $$ $$-$$9 respectively at 25oC. If the mixture of these two is washed with water, what is the concentration of Ca2+ ions in water ?
A
5.831 $$ \times $$ 10$$-$$5 M
B
6.856 $$ \times $$ 10$$-$$5 M
C
3.606 $$ \times $$ 10$$-$$5 M
D
7.746 $$ \times $$ 10$$-$$5 M

Explanation

CaCO3 $$ \to $$ Ca2+ + CO32-
x x

CaC2O4 $$ \to $$ Ca2+ + C2O42-
y y


[Ca2+] = x + y

Now, Ksp (CaCO3) = [Ca2+] [CO3 2-]

or 4.7 × 10–9 = (x + y)x .......(1)

similarly, Ksp (CaC2O4) = [Ca2+] [C2O42–]

or 1.3 × 10–9 = (x + y)y .......(2)

Dividing equation (1) and (2), we get

$${x \over y} = 3.6$$

$$ \therefore $$ x = 3.6y

Putting in equation (2) we get

y(3.6y + y) = 1.3 × 10–9

$$ \Rightarrow $$ y = 1.68 $$ \times $$ 10-5

and x = 3.6 $$ \times $$ 1.68 $$ \times $$ 10-5 = 6.048 $$ \times $$ 10-5

$$ \therefore $$ [Ca2+] = (x + y) = (6.048 $$ \times $$ 10-5) + (1.68 $$ \times $$ 10-5)

$$ \therefore $$ [Ca2+] = 7.746 × 10–5 M
2
MCQ (Single Correct Answer)

NEET 2013 (Karnataka)

At 100oC the Kw of water is 55 times its value at 25oC. What will be the pH of neutral solution? (log 55 = 1.74)
A
7.00
B
7.87
C
5.13
D
6.13

Explanation

Kw at 25oC = 1 × 10–14

At 25ºC

Kw = [H+] [OH] = 10–14

At 100°C (given)

Kw = [H+] [OH] = 55 × 10–14

for a neutral solution

[H+] = [OH]

[H+]2 = 55 × 10–14

or [H+] = (55 × 10–14)1/2

pH = – log [H+]

On taking log on both side

– log [H+] = –log (55 × 10–14)1/2

$$ \Rightarrow $$ pH = $${1 \over 2}$$ - log55 - 14log10

$$ \Rightarrow $$ pH = 6.13
3
MCQ (Single Correct Answer)

NEET 2013 (Karnataka)

Accumulation of lactic acid (HC3H5O3), a monobasic acid in tissues leads to pain and a feeling of fatigue. In a 0.10 M aqueous solution, lactic acid is 3.7% dissociates. The value of dissociation constant, Ka, for this acid will be
A
1.4 $$ \times $$ 10$$-$$5
B
1.4 $$ \times $$ 10$$-$$4
C
3.7 $$ \times $$ 10$$-$$4
D
2.8 $$ \times $$ 10$$-$$4

Explanation

$$\alpha = \sqrt {{{{K_a}} \over c}} $$

$$ \Rightarrow $$ 0.037 = $$\sqrt {{{{K_a}} \over {0.10}}} $$

$$ \Rightarrow $$ Ka = (0.037)2 $$ \times $$ 0.10

= 1.37 ×10–4

$$ \simeq $$ 1.4 $$ \times $$ 10$$-$$4
4
MCQ (Single Correct Answer)

NEET 2013

Which of these is least likely to act as a lewis base ?
A
BF3
B
PF3
C
CO
D
F$$-$$

Explanation

BF3 acts as Lewis acid. It is electron pair acceptor.

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