AIPMT 2005 | Ionic Equilibrium Question 47 | Chemistry

AIPMT 2005

MCQ (Single Correct Answer)

-1

H₂S gas when passed through a solution of cations containing HCl precipitates the cations of second group of qualitative analysis but not those belonging to the fourth group. It is because

presence of HCl decreases the sulphide ion concentration

solubility product of group II sulphides is more than that of group IV sulphates

presence of HCl increases the sulphide ion concentration

sulphides of group IV cations are unstable in HCl.

AIPMT 2005

MCQ (Single Correct Answer)

-1

At 25^oC, the dissociation constant of a base, BOH, is 1.0 $$ \times $$ 10^$$-$$12. The concentration of hydroxyl ions in 0.01 M aqueous solution of the base would be

1.0 $$ \times $$ 10^$$-$$5 mol L^$$-$$1

1.0 $$ \times $$ 10^$$-$$6 mol L^$$-$$1

2.0 $$ \times $$ 10^$$-$$6 mol L^$$-$$1

1.0 $$ \times $$ 10^$$-$$7 mol L^$$-$$1

AIPMT 2004

MCQ (Single Correct Answer)

-1

The rapid change of pH near the stoichiometric point of an acid-base titration is the basis of indicator detection. pH of the solution is related to ratio of the concentrations of the conjugate acid (HIn) and base (In^$$-$$) forms of the indicator by the expression

$$\log {{\left[ {I{n^ - }} \right]} \over {\left[ {HIn} \right]}} = p{K_{In}} - pH$$

$$\log {{\left[ {HIn} \right]} \over {\left[ {I{n^ - }} \right]}} = p{K_{In}} - pH$$

$$\log {{\left[ {HIn} \right]} \over {\left[ {I{n^ - }} \right]}} = pH - p{K_{In}}$$

$$\log {{\left[ {I{n^ - }} \right]} \over {\left[ {HIn} \right]}} = pH - p{K_{In}}$$

AIPMT 2004

MCQ (Single Correct Answer)

-1

The solubility product of a sparingly soluble salt AX₂ is 3.2 $$ \times $$ 10^$$-$$11. Its solubility (in moles/L) is

5.6 $$ \times $$ 10^$$-$$6

3.1 $$ \times $$ 10^$$-$$4

2 $$ \times $$ 10^$$-$$4

4 $$ \times $$ 10^$$-$$4

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