NEET 2016 Phase 1 | Wave Optics Question 17 | Physics

NEET 2016 Phase 1

MCQ (Single Correct Answer)

-1

The intensity at the maximum in a Young's double slit experiment is $$I$$₀. Distance between two slits is d = 5$$\lambda $$, where $$\lambda $$ is the wavelength of light used in the expreriment. What will be the intensity in front of one of the slits on the screen placed at a distance D = 10d ?

$${3 \over 4}{I_0}$$

$${{{I_0}} \over 2}$$

I₀

$${{{I_0}} \over 4}$$

AIPMT 2015

MCQ (Single Correct Answer)

-1

At the first minimum adjacent to the central maximum of a single-slit diffraction pattern, the phase difference between the Huygen's wavelet from the edge of the slit and the wavelet from the midpoint of the slit is

$$\pi $$ radian

$${\pi \over 8}$$ radian

$${\pi \over 4}$$ radian

$${\pi \over 2}$$ radian

AIPMT 2015

MCQ (Single Correct Answer)

-1

Two slits in Young's experiment have widths in the ratio 1 : 25. The ratio of intensity at the maxima and minima in the interference pattern, $${{{I_{max}}} \over {{I_{min}}}}$$ is

$${{49} \over {121}}$$

$${4 \over 9}$$

$${9 \over 4}$$

$${{121} \over {49}}$$

AIPMT 2015 Cancelled Paper

MCQ (Single Correct Answer)

-1

For a parallel beam of monochromatic light of wavelength '$$\lambda $$' , diffraction is produced by a single slit whose width 'a' is of the order of the wavelength of the light. If 'D' is the distance of the screen from the slit, the wifth of the central maxima will be

$${{Da} \over \lambda }$$

$${{2Da} \over \lambda }$$

$${{2D\lambda } \over a}$$

$${{D\lambda } \over a}$$

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