1
NEET 2017
MCQ (Single Correct Answer)
+4
-1
Change Language
The ratio of resolving powers of an optical microscope for two wavelength $$\lambda $$1 = 4000 $$\mathop A\limits^ \circ $$ and $${\lambda _2}$$ = 6000 $$\mathop A\limits^ \circ $$ is
A
9 : 4
B
3 : 2
C
16 : 81
D
8 : 27
2
NEET 2016 Phase 2
MCQ (Single Correct Answer)
+4
-1
Change Language
A linear aperture whose width is 0.02 cm is placed immediately in front of a lens of focal length 60 cm. The aparture is illuminated normally by a parallel beam of wavelength 5 $$ \times $$ 10$$-$$5 cm. The distance of the first dark band of the diffraction pattern from the centre of the screen is
A
0.10 cm
B
0.25 cm
C
0.20 cm
D
0.15 cm
3
NEET 2016 Phase 2
MCQ (Single Correct Answer)
+4
-1
Change Language
The interference pattern is obtained with two coherent light sources of intensity ratio n. In the interference pattern, the ratio $${{{I_{max}} - {I_{\min }}} \over {{I_{max}} + {I_{min}}}}$$ will be
A
$${{\sqrt n } \over {n + 1}}$$
B
$${{2\sqrt n } \over {n + 1}}$$
C
$${{\sqrt n } \over {{{\left( {n + 1} \right)}^2}}}$$
D
$${{2\sqrt n } \over {{{\left( {n + 1} \right)}^2}}}$$
4
NEET 2016 Phase 1
MCQ (Single Correct Answer)
+4
-1
Change Language
The intensity at the maximum in a Young's double slit experiment is $$I$$0. Distance between two slits is d = 5$$\lambda $$, where $$\lambda $$ is the wavelength of light used in the expreriment. What will be the intensity in front of one of the slits on the screen placed at a distance D = 10d ?
A
$${3 \over 4}{I_0}$$
B
$${{{I_0}} \over 2}$$
C
I0
D
$${{{I_0}} \over 4}$$

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