AIPMT 2001 | Some Basic Concepts of Chemistry Question 48 | Chemistry

AIPMT 2001

MCQ (Single Correct Answer)

-1

Specific volume of cylinfrical virus particle is 6.02 $$ \times $$ 10^$$-$$2 cc/g whose radius and length are 7 $$\mathop A\limits^ \circ $$ and 10 $$\mathop A\limits^ \circ $$ respectively. If _NA = 6.02 $$ \times $$ 10²³, find molecular weight of virus.

15.4 kg/mol

1.54 $$ \times $$ 10⁴ kg/mol

3.08 $$ \times $$ 10⁴ kg/mol

3.08 $$ \times $$ 10³ kg/mol

AIPMT 2001

MCQ (Single Correct Answer)

-1

Percentage of Se in peroxidase anhydrous enzyme is 0.5% by weight (at. wt. = 78.4) then minimum molecular weight of peroxide anhydrous enzyme is

1.568 $$ \times $$ 10⁴

1.568 $$ \times $$ 10³

15.68

2.136 $$ \times $$ 10⁴

AIPMT 2001

MCQ (Single Correct Answer)

-1

Molarity of liquid HCl, if density of solution is 1.17 g/ce is

36.5

18.25

32.05

42.10

AIPMT 2000

MCQ (Single Correct Answer)

-1

Oxidation numbers of A, B, C are + 2, +5 and $$-$$2 respectively. Possible formula of compound is

A₂(BC₂)₂

A₃(BC₄)₂

A₂(BC₃)₂

A₃(B₂C)₂

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