NEET 2013 | Some Basic Concepts of Chemistry Question 30 | Chemistry

NEET 2013

MCQ (Single Correct Answer)

-1

How many grams of concentrated nitric acid solution should be used to prepare 250 mL of 2.0 M HNO₃? The concentrated acid is 70% HNO₃.

70.0 g conc. HNO₃

54.0 g conc. HNO₃

45.0 g conc. HNO₃

90.0 g conc. HNO₃

NEET 2013

MCQ (Single Correct Answer)

-1

6.02 $$ \times $$ 10²⁰ molecules of urea present in 100 mL of its solution. The concentration of solution is

0.001 M

0.1 M

0.02 M

0.01 M

AIPMT 2011 Mains

MCQ (Single Correct Answer)

-1

Which has the maximum number of molecules among the following ?

44 g CO₂

48 g O₃

8 g H₂

64 g SO₂

AIPMT 2010 Prelims

MCQ (Single Correct Answer)

-1

The number of atoms in 0.1 mol of a triatomic gas is (N_A = 6.02 $$ \times $$ 10²³ mol^$$-$$1)

6.026 $$ \times $$ 10²²

1.806 $$ \times $$ 10²³

3.600 $$ \times $$ 10²³

1.800 $$ \times $$ 10²²

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