NEET 2023 | Motion in a Plane Question 4 | Physics

NEET 2023

MCQ (Single Correct Answer)

-1

A horizontal bridge is built across a river. A student standing on the bridge throws a small ball vertically upwards with a velocity $$4 \mathrm{~m} \mathrm{~s}^{-1}$$. The ball strikes the water surface after $$4 \mathrm{~s}$$. The height of bridge above water surface is (Take $$g=10 \mathrm{~m} \mathrm{~s}^{-2}$$ )

60 m

64 m

68 m

56 m

NEET 2022 Phase 2

MCQ (Single Correct Answer)

-1

A cricket ball is thrown by a player at a speed of 20 m/s in a direction 30$$^\circ$$ above the horizontal. The maximum height attained by the ball during its motion is

(g = 10 m/s²)

25 m

5 m

10 m

20 m

NEET 2022 Phase 1

MCQ (Single Correct Answer)

-1

A ball is projected with a velocity, 10 ms^$$-$$1, at an angle of 60$$^\circ$$ with the vertical direction. Its speed at the highest point of its trajectory will be

Zero

5$$\sqrt3$$ ms^$$-$$1

5 ms^$$-$$1

10 ms^$$-$$1

NEET 2021

MCQ (Single Correct Answer)

-1

A particle moving in a circle of radius R with a uniform speed takes a time T to complete one revolution.

If this particle were projected with the same speed at an angle '$$\theta$$' to the horizontal, the maximum height attained by it equals 4R. The angle of projection, $$\theta$$, is then given by :

$$\theta = {\sin ^{ - 1}}{\left( {{{2g{T^2}} \over {{\pi ^2}R}}} \right)^{1/2}}$$

$$\theta = {\cos ^{ - 1}}{\left( {{{g{T^2}} \over {{\pi ^2}R}}} \right)^{1/2}}$$

$$\theta = {\cos ^{ - 1}}{\left( {{{{\pi ^2}R} \over {g{T^2}}}} \right)^{1/2}}$$

$$\theta = {\sin ^{ - 1}}{\left( {{{{\pi ^2}R} \over {g{T^2}}}} \right)^{1/2}}$$

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