AIPMT 2015 Cancelled Paper | Moving Charges and Magnetism Question 25 | Physics

AIPMT 2015 Cancelled Paper

MCQ (Single Correct Answer)

-1

An electron moving in a circular orbit of radius r makes n rotations per second. The magnetic field produced at the centre has magnitude

$${{{\mu _0}{n^2}e} \over r}$$

$${{{\mu _0}ne} \over {2r}}$$

$${{{\mu _0}ne} \over {2\pi r}}$$

Zero

AIPMT 2015 Cancelled Paper

MCQ (Single Correct Answer)

-1

A conducting square frame of side 'a' and a long straight wire carrying current $$I$$ are located in the same plane as shown in the figure. The frame moves to the right with a constant velocity 'V'. The emf induced in the frame will be proportional to

AIPMT 2015 Cancelled Paper Physics - Moving Charges and Magnetism Question 62 English

AIPMT 2015 Cancelled Paper Physics - Moving Charges and Magnetism Question 62 English

$${1 \over {{{\left( {2x + a} \right)}^2}}}$$

$${1 \over {\left( {2x - a} \right)\left( {2x + a} \right)}}$$

$${1 \over {{x^2}}}$$

$${1 \over {{{\left( {2x - a} \right)}^2}}}$$

AIPMT 2015 Cancelled Paper

MCQ (Single Correct Answer)

-1

A wire carrying current $$I$$ has the shape shown in adjoining figure.

AIPMT 2015 Cancelled Paper Physics - Moving Charges and Magnetism Question 63 English

AIPMT 2015 Cancelled Paper Physics - Moving Charges and Magnetism Question 63 English

Linear parts of the wire are very long and parallel to X-axis while semicircular protion of radius R is lying in Y-Z plane. Magtnetic field at pont $$O$$ is

$$\overrightarrow B = - {{{\mu _0}I} \over {4\pi R}}\left( {\pi \widehat i + 2\widehat k} \right)$$

$$\overrightarrow B = {{{\mu _0}I} \over {4\pi R}}\left( {\pi \widehat i - 2\widehat k} \right)$$

$$\overrightarrow B = {{{\mu _0}I} \over {4\pi R}}\left( {\pi \widehat i + 2\widehat k} \right)$$

$$\overrightarrow B = - {{{\mu _0}I} \over {4\pi R}}\left( {\pi \widehat i - 2\widehat k} \right)$$

AIPMT 2014

MCQ (Single Correct Answer)

-1

Two identical long conducting wires $$AOB$$ and $$COD$$ are placed at right angle to each other, with one above other such that $$O$$ is their common point for the two. The wires carry $$I$$₁ and $$I$$₂ currents, respectively. Point $$P$$ is lying at distance f from $$O$$ along a direction perpendicular to the plane containing the wires. The magnetic field at the point $$P$$ will be

$${{{\mu _0}} \over {2\pi d}}\left( {{{{I_1}} \over {{I_2}}}} \right)$$

$${{{\mu _0}} \over {2\pi d}}\left( {{I_1} + {I_2}} \right)$$

$${{{\mu _0}} \over {2\pi d}}\left( {I_1^2 - I_2^2} \right)$$

$${{{\mu _0}} \over {2\pi d}}{\left( {I_1^2 + I_2^2} \right)^{1/2}}$$

PREVIOUS NEXT

NEET Subjects

Biology

Botany

Zoology

Human Health and Diseases Body Fluids and Its Circulation Locomotion and Movement Neural Control and Coordination Reproduction in Organisms Reproductive Health Structural Organisation in Animals Digestion and Absorption Excretory Products and Their Elimination Chemical Coordination and Integration Human Reproduction Animal Kingdom Breathing and Exchange of Gases Evolution