1
AIPMT 2004
MCQ (Single Correct Answer)
+4
-1
To convert a galvanometer into a voltmeter one should connect a
A
high resistance in series with galvanometer
B
low resistance in series with galvanometer
C
high resistance in parallel wilh galvanometer
D
low resistance in parallel with galvanometer.
2
AIPMT 2004
MCQ (Single Correct Answer)
+4
-1
A galvanometer of 50 ohm resistance has 25 divisions. A current of 4 $$ \times $$ 10$$-$$4 ampere gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of 25 volts, it should be connected with a resistance of
A
$$2500\,\Omega $$ as a shunt
B
2450 $$\Omega $$ as a shunt
C
2550 $$\Omega $$ in series
D
2450 $$\Omega $$ in series
3
AIPMT 2003
MCQ (Single Correct Answer)
+4
-1
A long solenoid carrying a current producess a magnetic field B along its axis. If the current is doubled and the number of turns per cm is halved, the new value of the magnetic field is
A
B/2
B
B
C
2B
D
4B
4
AIPMT 2003
MCQ (Single Correct Answer)
+4
-1
A charged particle moves through a magnetic field in a firection perpendicular to it. Then the
A
speed of the particle remains unchanged
B
direction of the particle remains unchanged
C
acceleration remains unchanged
D
velocity remains unchanged
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