AIPMT 2012 Mains | Moving Charges and Magnetism Question 35 | Physics

AIPMT 2012 Mains

MCQ (Single Correct Answer)

-1

A proton carrying 1 MeV kinetic energy is moving in a circular path of radius R in uniform magnetic field. What should be the energy of an $$\alpha $$-particle to describe a circle of same radius in the same field?

2 MeV

1 MeV

0.5 MeV

4 MeV

AIPMT 2012 Prelims

MCQ (Single Correct Answer)

-1

A milli voltmeter of 25 milli volt range is to be converted into an ammeter of 25 ampare range. The value (in ohm) of neccessary shunt will be

0.001

0.01

0.05

AIPMT 2012 Prelims

MCQ (Single Correct Answer)

-1

Two similar coils of radius R are lying concentrically with their planes at right angles to each other. The currents flowing in them are $$I$$ and 2$$I$$, respectively. The resultant magnetic field induction at the centre will be

$${{\sqrt 5 {\mu _0}I} \over {2R}}$$

$${{\sqrt 5 {\mu _0}I} \over R}$$

$${{{\mu _0}I} \over {2R}}$$

$${{{\mu _0}I} \over R}$$

AIPMT 2012 Prelims

MCQ (Single Correct Answer)

-1

An alternating electric field, of frequency $$v$$, is applied across the does (radius = R) of a cyclotron that is being used to accelerate protons (mass = m). The operating magnetic field (B) used in the cyclotron and the kinetic energy (K) of the proton beam, produced by it, are given by

$$B = {{m\upsilon } \over e}$$ and $$K = 2m{\pi ^2}{\upsilon ^2}{R^2}$$

$$B = {{2\pi m\upsilon } \over e}$$ $$K = {m^2}\pi \upsilon {R^2}$$

$$B = {{2\pi m\upsilon } \over e}$$ $$K = 2m{\pi ^2}{v^2}{R^2}$$

$$B = {{m\upsilon } \over e}$$ $$K = {m^2}\pi \upsilon {R^2}$$

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